Re^4: Spliting array into nested sequential arrays

My assumption was that I no longer had @array1 to work with and had to create the final sorted array from @newarray.

Comment on Re^4: Spliting array into nested sequential arrays

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Re^5: Spliting array into nested sequential arrays by boftx (Deacon) on Oct 29, 2014 at 02:17 UTC
Never assume what is required. Trust me. Ask and ask again and preferably get the specs in writing. If the spec is ambiguous, then I assure you that you will have to either do it over or have people call your code naive at best. :) You must always remember that the primary goal is to *drain the swamp* even when you are hip-deep in alligators.	[reply]
Re^6: Spliting array into nested sequential arrays by Hameed (Acolyte) on Oct 29, 2014 at 03:38 UTC
Oh of course, I get that... :D This was an interview situation and it was not just an assumption but kind of a logical thought process from their question. "Now from this, do such and such..."	[reply]