Re^4: regex renaming with existing files

Thank you for your reply. I however was having the same issue after assigning $counter = 1 & ++$counter. I then created a for loop, as following, and now it's working as I wanted-

# replaced $counter with $i.
for ($i=1; $i<10; $i++){
...........
}
[download]

Result:
folder1, folder1.[1], folder1.[2], folder1.[3]...etc.
[download]

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Re^5: regex renaming with existing files by GrandFather (Saint) on Nov 04, 2014 at 20:12 UTC
Show us the actual code you tried and tell us what issue you saw. `$counter = 1 & ++$counter` is rather unlikely code and probably doesn't do anything like what you expect, although it's hard to tell what you expect. Don't use the C style for loop. Instead use: `for my $counter (1 .. 9) { ... }` [download] which is much clearer and a lot harder to get wrong. Perl is the programming world's equivalent of English	[reply] [d/l] [select]

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Re^5: regex renaming with existing files
by GrandFather (Saint) on Nov 04, 2014 at 20:12 UTC

Show us the actual code you tried and tell us what issue you saw. $counter = 1 & ++$counter is rather unlikely code and probably doesn't do anything like what you expect, although it's hard to tell what you expect.

Don't use the C style for loop. Instead use:

for my $counter (1 .. 9) {
    ...
}
[download]

which is much clearer and a lot harder to get wrong.

Perl is the programming world's equivalent of English

[reply]
[d/l]
[select]