in reply to changing copy of a hash changes original

Add print "$hash1{Quantity} - $hash2{Quantity}"; and you will see that they both have the same reference, in other words they are referencing the same anonymous hash.

CountZero

A program should be light and agile, its subroutines connected like a string of pearls. The spirit and intent of the program should be retained throughout. There should be neither too little or too much, neither needless loops nor useless variables, neither lack of structure nor overwhelming rigidity." - The Tao of Programming, 4.1 - Geoffrey James

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In Section Seekers of Perl Wisdom