Re^2: Is the number before, in or after the interval? using spaceship operator <=>

Hm.. yes.
And that is simpler solution with two basic comparisons:
map { ("-1", " 0", " 1")[ ($_ >= $l) + ($_ > $r) ] } -9 .. 10;

Comment on Re^2: Is the number before, in or after the interval? using spaceship operator <=> Download Code

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Re^3: Is the number before, in or after the interval? using spaceship operator <=> by LanX (Saint) on Nov 21, 2014 at 15:23 UTC
`($_ > $r) - ($_ < $l)` Should already do (can't test on Android :) update tested! =) `DB<41> sub tst { ($_ > $r) - ($_ < $l) } DB<42> $l=3;$r=6 => 6 DB<43> print tst(),"\t" for 0..9 => "" -1 -1 -1 0 0 0 0 1 1 1` [download] Cheers Rolf _{(addicted to the Perl Programming Language and ☆☆☆☆ :)}	[reply] [d/l] [select]