Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question: 

@a = (1..9);
@b = (a..g);

@c = @a . @b;

print "@c\n";

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why can't I do that?

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Re: concatenating arrays
by MZSanford (Curate) on Sep 07, 2001 at 17:50 UTC
    The reason it fails is because . is the string concatonation operator. So, to concatonate two arrays you have to be a bit more explicit. something like :
    @c = (@a,@b);
# .. or , the better approach (faster)
push(@c,@b,@a);

    [download]

    update : corrected my stupid push mistake ... need to think before i submit. oops. thanks to those who noticed.
    can't sleep clowns will eat me
    -- MZSanford
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      *BZZZZZZZT* Nope. 
      # If initializing, this is clearer.
my @c = (@a, @b);
# .. or ... (now, more correct)
my @c;
push @c, @a, @b;

      [download]
      push will take an array and a list, push the list onto the end of the array, and return the new number of elements.

      ------
      We are the carpenters and bricklayers of the Information Age.

      Don't go borrowing trouble. For programmers, this means Worry only about what you need to implement.

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