in reply to Re^3: Closure confusion in Tkx (declarations in loops - inner vs outer)
in thread Closure confusion in Tkx
Think of lexicals in a scope like having a different references each time the scope is passed at runtime.
But - like already demonstrated - the first part of the c-style for is outside the block to be implemented as a while.
A lexical declaration in a scope reserves - at run time - a storage place in memory which is released at the end of scope.
No release happens if the ref counter isn't 0, like when the lexical is used in a closure.
So if the last lexical was released it might happen that the ref is reused, but it's better to assume they aren't the same variable.
DB<8> for my $x (1..3) { print \$x } SCALAR(0x3450e50)SCALAR(0x3450e50)SCALAR(0x3450e50) DB<9> for my $x (1..2) { print \$x; $a = sub {$x} } SCALAR(0x3459b20)SCALAR(0x3328238)
$x has different refs in line 9 because the first $x is captured in a closure and not relased.
Hence Perl can't reuse the reference.
HTH! :)
Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery
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