in reply to Complex regex question

Yet another way. Pre-5.10 compatible; avoids explicit captures. Unfortunately, rather heavy on the look-arounds.

c:\@Work\Perl\monks>perl -wMstrict -MData::Dump -le "my $s = qq{a aa 21a a 123 a b9 b bb aa1 1aa @ARGV}; dd $s; ;; my @captures = $s =~ m{ \b \d+ (?= (?: a|b) \b) | (?<= \b (?: a|b)) \d+ \b | \b (?: a|b) (?= \d) | (?<= \d) (?: a|b) \b }xmsg; dd \@captures; " "aa11 11aa [b42] (12a)" "a aa 21a a 123 a b9 b bb aa1 1aa aa11 11aa [b42] (12a)" [21, "a", "b", 9, "b", 42, 12, "a"]


Give a man a fish:  <%-{-{-{-<

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Re^2: Complex regex question
by rsFalse (Chaplain) on Sep 25, 2019 at 18:52 UTC
    One more variant:
    #!/usr/bin/perl # https://perlmonks.org/?node_id=11106665 use strict; use warnings; use Data::Dumper; $Data::Dumper::Indent = 0; my $string_three = "a aa 21a a 123 a b9 b bb aa1 1aa aa11 11aa [b42] ( +12a)"; my @captures = $string_three =~ m{ \b ([ab])? (\d+) ([ab])? \b (?(?{ 1 != grep defined, $1, $3 }) (*FAIL) ) }xmsg; print "RESULTS: ", ( Dumper \@captures ), "\n";
    RESULTS: $VAR1 = [undef,'21','a','b','9',undef,'b','42',undef,undef,'1 +2','a'];
    It generates triplets with one undefined value ($1 or $3), but you can grep defined values as AnomalousMonk mensioned.

    EDIT:
    Sorry for mistake. I changed condition "2 == grep defined, $1, $3" to "1 != grep defined, $1, $3", because one of $1 or $3 must be defined.


    ADDED:
    my @captures = $string_three =~ m{ \b ([ab])? (\d+) (?(1) | ([ab]) ) \b }xmsg;
    Similar approach using conditional. It captures in same way.

    ADDED-2:
    Also:
    my @captures = $string_three =~ m{ \b ([ab])? (\d+) (?(1) (*ACCEPT) ) ([ab]) \b }xmsg;