in reply to Counting elements in array of cases

And here is another solution:

#!/usr/bin/perl use strict; use warnings; my @AoH = ({qw/ targetL foisonnement origin AMG count 1 /}, {qw/ targetL foisonnement origin IDBR count 1 /}, {qw/ origin IWWF targetL gonfler count 1 /}, {qw/ origin IWWF targetL due count 1 /}, {qw/ origin IWWF targetL due count 1 /}); my @AoHfinal = ({'targetL' => 'foisonnement', 'origin' => 'AMG IDBR', 'count' => '2 +'}, {'targetL' => 'gonfler', 'origin' => 'IWWF', 'count' => '1' +}, {'targetL' => 'due', 'origin' => 'IWWF', 'count' => '2' +}); my %out = (); my %seen = (); my @out = (); foreach (@AoH) { if ($out{$_->{targetL}}) { push @{$out{$_->{targetL}}->{origin}}, $_->{origin} unless $seen{$_->{targetL}}{$_->{origin}}++; $out{$_->{targetL}}{count} += $_->{count}; } else { my $row = {targetL => $_->{targetL}, origin => [$_->{origin}], count => $_->{count}}; $out{$_->{targetL}} = $row; push @out, $row; $seen{$_->{targetL}}{$_->{origin}} = 1; } } $_->{origin} = join(' ', @{$_->{origin}}) for @out; use Test::More; is_deeply(\@out, \@AoHfinal); done_testing(); __END__

I think that the most notable difference in my solution is keeping the running origin values as an array until the very end, instead of repeating string manipulations. This preserves the order of both the targets and the origins while using only the core language — and a core module to verify the result.

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Re^2: Counting elements in array of cases
by LanX (Saint) on Sep 27, 2019 at 23:55 UTC
    > while using only the core language — and a core module to verify the result.

    As far as I can see all solutions so far - with the exception of the sqlite "solution" - used core modules.

    Cheers Rolf
    (addicted to the Perl Programming Language :)
    Wikisyntax for the Monastery FootballPerl is like chess, only without the dice