Re: how to self define a operator (private method)

Not exactly what you want, but since $p and $t seem to return objects, you are able to either

If that's too much of interference you can also define a private method

my $meth = sub { 
    $_[0] .= $_[1]->reshape($_[0]->dims) 
};
[download]

And call it with

$t(1:2,0)->$meth( $p(0,1:2) )

from inside the same scope (untested)

This should come close to what you want.

HTH!

Cheers Rolf
_{(addicted to the Perl Programming Language :)

Wikisyntax for the Monastery
FootballPerl is like chess, only without the dice}

demo


  DB<9> $op = sub { $_[0] + $_[1] }

  DB<10> p 4->$op(5)
9
  DB<11>
[download]

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Re^2: how to self define a operator (private method) by toothedsword (Sexton) on Oct 22, 2019 at 15:10 UTC
Great! It is a good method. Thanks!	[reply]