Re: Replacing between patterns

I want to also catch everything on the same line of XYZ.

You can say that explicitly: s/ABC(.*?)XYZ\N*\n/\[DATA\]\n/s will produce your desired output. (Note \N was added in 5.12, for older versions you can say e.g. [^\n].)

Minor edits shortly after posting.

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Re^2: Replacing between patterns by ovedpo15 (Pilgrim) on Oct 28, 2019 at 13:12 UTC
Thanks! The old version is being supported on new versions as well?	[reply]
Re^3: Replacing between patterns by haukex (Archbishop) on Oct 28, 2019 at 13:15 UTC
The old version is being supported on new versions as well? Yes, it is. Here's another backwards-compatible alternative: `s/ABC(?s:.?)XYZ./[DATA]/`	[reply] [d/l]