Re: using basename on a list of filesnames

You are in a loop of filenames. Try

my $basename = basename ($file, ".psd");
print "$basename\n";
[download]

The way forward always starts with a minimal test.

Comment on Re: using basename on a list of filesnames Download Code

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Re^2: using basename on a list of filesnames by flieckster (Scribe) on Nov 13, 2019 at 02:08 UTC
that didn't seem to work `Use of uninitialized value $_[0] in substitution (s///) at /System/Lib +rary/Perl/5.18/File/Basename.pm line 341, <GEN0> line 10. fileparse(): need a valid pathname` [download] i also tried. `my $basename = basename (@TIFFfolder_list, ".psd"); print "$basename\n";` [download] that only gave one filename output from the array.	[reply] [d/l] [select]
Re^3: using basename on a list of filesnames by 1nickt (Canon) on Nov 13, 2019 at 03:51 UTC
Did you add a debug print statement inside the loop to see what you are passing to `basename()` in `$file`? It really works: `$ perl -MFile::Basename -wE 'say basename("foo.psd",".psd")' foo` [download] ... but passing an undefined value does not: `$ perl -MFile::Basename -wE 'say basename(undef,".psd")' Use of uninitialized value $_[0] in substitution (s///) at /Users/1nic +kt/perl5/perlbrew/perls/perl-5.30.0/lib/5.30.0/File/Basename.pm line +341. fileparse(): need a valid pathname at -e line 1.` [download] The way forward always starts with a minimal test.	[reply] [d/l] [select]