Re: passing an array without a name to pop()

Your list of numbers is a list; the problem is that pop is the source of the surrounding context and provides a scalar one. If you check the prototype, pop is ";+" and + is a bit weird. Thus quoth perlsub:

    The "+" prototype is a special alternative to "$" that will act li
+ke
    "\[@%]" when given a literal array or hash variable, but will othe
+rwise
    force scalar context on the argument. This is useful for functions
+ which
    should accept either a literal array or an array reference as the
    argument:
[download]

Update: Tweaked formatting.

The cake is a lie.
The cake is a lie.
The cake is a lie.

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Re^2: passing an array without a name to pop() by haukex (Archbishop) on Dec 03, 2019 at 20:51 UTC
If you check the prototype, pop is `";+"` No, not anymore, this was an experiment added in Perl 5.14 and removed in 5.24; see "Array and hash container functions accept references" (aka "autoderef") in perlexperiment. Its prototype has gone back to `;\@`, like it was in 5.12 and below. The removal of the feature is why the "Experimental pop on scalar is now forbidden" error happens in the first place.	[reply] [d/l] [select]
Re^3: passing an array without a name to pop() by Fletch (Bishop) on Dec 03, 2019 at 21:26 UTC
Derp! That's what I get for trying it on my older desktop install instead of a close-to-current version. The cake is a lie. The cake is a lie. The cake is a lie.	[reply]