in reply to Re^4: RFC: "assignary" operator ?= :
in thread RFC: "assignary" operator ?= :

> Second, the sub you wrote isn't at all ternary in any way

It's an XY problem, the use case wasn't ternary from the beginning.

But you're welcome to impress us with a better solution.

Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery FootballPerl is like chess, only without the dice

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