in reply to Re: RFC: "assignary" operator ?= : ( source Filter::PPI::Transform )
in thread RFC: "assignary" operator ?= :
Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery
FootballPerl is like chess, only without the dice
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Re^3: RFC: "assignary" operator ?= : ( source Filter::PPI::Transform )
by tobyink (Canon) on Dec 11, 2019 at 13:32 UTC | |
by LanX (Saint) on Dec 11, 2019 at 16:13 UTC |