in reply to Re^2: 'xor' operator is not a sibling to 'or' and 'and'?
in thread 'xor' operator is not a sibling to 'or' and 'and'?

No, that's completely wrong. The reason $TRUE and $TRUE doesn't necessarily return 1 has nothing to do with why $TRUE xor $TRUE doesn't return 1.

$TRUE and $TRUE doesn't necessarily return 1 because it's more useful to return its RHS.

$TRUE xor $TRUE doesn't return 1 because that would be wrong.

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