in reply to Re: Regex boundary match (updated demo code)
in thread Regex boundary match

Thanks. I ended up with ([^\-]). Is your version quicker? Or negligible difference? (its going to be run quite a lot of times)

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Re^3: Regex boundary match (updated demo code)
by AnomalousMonk (Archbishop) on Feb 08, 2020 at 15:55 UTC
    I ended up with ([^\-]). ... difference?

    It depends on exactly what you want.  ([^\-]) requires a character match and consumes a character. As LanX pointed out,  ([^\-]|$) consumes a character if it can. Neither seem to do what you want:

    c:\@Work\Perl\monks>perl -wMstrict -le "my $s = 'test atest atested tested test- -test test .test test. test' +; ;; $s =~ s/\b(test)([^-])/DONE/g; print qq{'$s'}; " 'DONEatest atested DONEd test- -DONEDONE.DONEDONE test' c:\@Work\Perl\monks>perl -wMstrict -le "my $s = 'test atest atested tested test- -test test .test test. test' +; ;; $s =~ s/\b(test)([^-]|$)/DONE/g; print qq{'$s'}; " 'DONEatest atested DONEd test- -DONEDONE.DONEDONE DONE'
    Maybe this does:
    c:\@Work\Perl\monks>perl -wMstrict -le "my $s = 'test atest atested tested test- -test test .test test. test' +; ;; $s =~ s/\b(test)(?!-)\b/DONE/g; print qq{'$s'}; " 'DONE atest atested tested test- -DONE DONE .DONE DONE. DONE'

    Update: Just noticed from the timestamps that ultranerds already decided to go with LanX's suggestion. :)


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