Re^2: Announcing Perl 7

... it would also remove the need to specify a perl version in order to use non-experimental, permanent features that that particular version brings. For example, need to add use v5.10; to use //= with perl 5.10.

Perhaps I've misunderstood you but I don't think that would be a change. I can quite happily use defined-or-equals without such a declaration in 5.10 (admittedly 5.10.1 which is the nearest version to which I have access - is it different for 5.10.0?).

$ perl -v | head -3

This is perl, v5.10.1 (*) built for x86_64-linux-thread-multi

$ perl -e '$z //= 20; print "$z\n";'
20
$
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Re^3: Announcing Perl 7 by parv (Parson) on Jun 25, 2020 at 13:26 UTC
Thanks much, hippo, for correcting me. I might have mixed my memory of use 'v5.10' so that program would not compile with perl 5.8 when using "//=". Would a better example be of `say` where in perl 5.32 still need to enable it via `feature` or `v5.10`?	[reply] [d/l] [select]
Re^4: Announcing Perl 7 by choroba (Cardinal) on Jun 25, 2020 at 14:32 UTC
Yes, there are two kinds of features, those using the feature pragma and those not using it. See my Syntax::Construct which tries to address it (and will be obsoleted by Perl 7, yay!) `map{substr$_->[0],$_->[1]\|\|0,1}[\\|\|{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^ARGV,3]`	[reply] [d/l]