Re: Multiple numeric not or compare in if statement

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Re^2: Multiple numeric not or compare in if statement by perlfan (Parson) on Jul 02, 2020 at 05:32 UTC
OP: maybe it was an oversight, but when changing the nested logic in a condition such as that you must necessarily change the higher level logic if you wish for the original to be ~~equivalent~~ exactly opposite to the negated version. `if (($a == 3) \|\| ($a == 77) \|\| ($a == 8)) -- is exactly opposite to -- if (($a != 3) && ($a != 77) && ($a != 8))` [download] Update: correct - meant to show exact opposites, used the most wrong possible to describe this.	[reply] [d/l]
Re^3: Multiple numeric not or compare in if statement by haukex (Archbishop) on Jul 02, 2020 at 07:44 UTC
`if (($a == 3) \|\| ($a == 77) \|\| ($a == 8)) -- is equivalent to -- if (($a != 3) && ($a != 77) && ($a != 8))` [download] No, those two aren't equivalent, they're exact opposites. It seems you didn't apply what you said: when changing the nested logic in a condition such as that you must necessarily change the higher level logic if you wish for the original to be equivalent to the negated version. `if (($a == 3) \|\| ($a == 77) \|\| ($a == 8)) -- is equivalent to -- if (!( ($a != 3) && ($a != 77) && ($a != 8) ))` [download]	[reply] [d/l] [select]
Re^4: Multiple numeric not or compare in if statement by perlfan (Parson) on Jul 02, 2020 at 13:27 UTC
Thanks, updated. Meant to show the exact opposite; said the opposite thing instead.	[reply]
Re^3: Multiple numeric not or compare in if statement by BillKSmith (Monsignor) on Jul 02, 2020 at 15:33 UTC
Refer: DeMorgan's_laws Bill	[reply]