Re: Calling perl from zsh w/ vars

I had to look for what .zsh meant. I guess this is a Mac/Apple thing.
Searching for a count of matching pattern lines, normally uses grep, there is an option to print the number of lines matched.
Perl is not required. However Perl can be used for that without requiring a shell program or grep. Why not use command line grep for "count of lines matching a pattern"?

Comment on Re: Calling perl from zsh w/ vars

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Re^2: Calling perl from zsh w/ vars by karlgoethebier (Abbot) on Jul 18, 2020 at 15:24 UTC
Ť...a Mac/Apple thingť He, yes and no 🤪😎 They replaced bash with zsh. See also. Best regards, Karl ŤThe Crux of the Biscuit is the Apostropheť `perl -MCrypt::CBC -E 'say Crypt::CBC->new(-key=>'kgb',-cipher=>"Blowfish")->decrypt_hex($ENV{KARL});'`Help	[reply] [d/l]
Re^3: Calling perl from zsh w/ vars by Marshall (Canon) on Jul 20, 2020 at 03:27 UTC
I like your link to Z Shell Wiki. My Unix shell experience is mainly with BASH.	[reply]
Re^4: Calling perl from zsh w/ vars by karlgoethebier (Abbot) on Jul 20, 2020 at 05:40 UTC
De rien. You may also take a look at ksh. Best regards, Karl ŤThe Crux of the Biscuit is the Apostropheť `perl -MCrypt::CBC -E 'say Crypt::CBC->new(-key=>'kgb',-cipher=>"Blowfish")->decrypt_hex($ENV{KARL});'`Help	[reply] [d/l]
Re^2: Calling perl from zsh w/ vars by Anonymous Monk on Jul 18, 2020 at 13:06 UTC
I guess this is a Mac/Apple thing. No.	[reply]