Re^2: $50 towards a laptop for the winner

> (Yes, the arrow operator accepts a scalar naming the method to call.)

Only half the truth, if $method is a code-ref it'll be called like a method (i.e. with $obj as first argument)

Sorry for nitpicking :)

Cheers Rolf
_{(addicted to the Perl Programming Language :)

Wikisyntax for the Monastery}

Comment on Re^2: $50 towards a laptop for the winner

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Re^3: $50 towards a laptop for the winner by jcb (Parson) on Jul 30, 2020 at 01:31 UTC
No real nitpick — I learned something new: the arrow operator also accepts a scalar containing a code reference.	[reply]

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