Re^6: How the auto-increment operator works?

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Re^7: How the auto-increment operator works? by AnomalousMonk (Archbishop) on Aug 02, 2020 at 01:00 UTC
For essentially the same reason that ++75 is 76 and not 86: `c:\@Work\Perl\monks>perl -wMstrict -le "my $s = '75'; printf qq{++'$s' -> }; ++$s; print qq{'$s'}; " ++'75' -> '76'` [download] Why would a "carry" ("B" -> "C") be generated by incrementing from "e" to "f"? Give a man a fish: `<%-{-{-{-<`	[reply] [d/l] [select]
Re^8: How the auto-increment operator works? by zapdos (Sexton) on Aug 02, 2020 at 01:20 UTC
Thank you very much. Now I have one more question: why `my $foo = "Zz"; print ++$foo;` prints "AAa" and not "AAaa"? Since there's two "z" characters and when one "z" character is incremented it produces "aa".	[reply] [d/l]
Re^9: How the auto-increment operator works? by LanX (Saint) on Aug 02, 2020 at 02:13 UTC
> > > If a new position is needed it'll adjust to the leftmost group. > my $foo = "Zz"; print ++$foo; prints "AAa" The A is a new position the next position to the right - which is causing the "carry" - is an uppercase character A. > when one "z" character is incremented it produces "aa". Again the left a is a new position, and the position to the right is a lowercase character. Cheers Rolf _{(addicted to the Perl Programming Language :) Wikisyntax for the Monastery}	[reply]
Re^10: How the auto-increment operator works? by AnomalousMonk (Archbishop) on Aug 02, 2020 at 02:45 UTC
Re^10: How the auto-increment operator works? by zapdos (Sexton) on Aug 02, 2020 at 03:17 UTC
Re^11: How the auto-increment operator works? by AnomalousMonk (Archbishop) on Aug 02, 2020 at 07:27 UTC
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Re^11: How the auto-increment operator works? by LanX (Saint) on Aug 02, 2020 at 13:59 UTC