Re^2: Flipping partial bits

The high bit does not need to be masked. Something like:

for my $x (0..0xff) {
    my $y = ( $x & 0x80 ) ?  -($x ^ 0xff) : $x;
    say "$x $y"
}
[download]

Comment on Re^2: Flipping partial bits Download Code

Replies are listed 'Best First'.
Re^3: Flipping partial bits by haukex (Archbishop) on Nov 14, 2020 at 12:08 UTC
The high bit does not need to be masked. Yes, that's true, though I felt the specs were a little bit lacking (hence my request for more examples), which is why I played it safe and showed how to do the masking too.	[reply]