Re^4: Regexp substitution using variables

> but I can't get back-references,

This works for me

  DB<44> $pat='(x)\1'

  DB<45> $mod='i'

  DB<46> 'xX' =~ /(?$mod)$pat/; say "$&:$1"
xX:x

  DB<47>
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Cheers Rolf
_{(addicted to the Perl Programming Language :)

Wikisyntax for the Monastery}

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Re^5: Regexp substitution using variables by MikeTaylor (Sexton) on Nov 26, 2020 at 10:34 UTC
Sorry, I think I was using the term "back-reference" incorrectly. I didn't mean referring back within the pattern to something earlier in the pattern, but referring in the substitution string to a captured sub-expression of the pattern. Something like `s/(foo\|bar)/He said "$1"/`.	[reply]