Re^2: How to shuffle this AoA

I'm seeing this pattern:

In the first (acceptable) result, all elements have a different order and no elements have been previously used.
In the second (unacceptable) result: the first element has the same order; the third element has been previously used.

I put this here to keep all the guesswork together. It was an afterthought; see code written earlier.

— Ken

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