Re^2: mysteries of regex substring matching

Same approach, but as a one liner:

  
  DB<5> p
0123456789012345678901234567890123456789

  DB<5> x / @{[ '(....)' x4 ]} (.+) /x
0  0123
1  4567
2  8901
3  2345
4  678901234567890123456789
  DB<6>
[download]

Cheers Rolf
_{(addicted to the Perl Programming Language :)

Wikisyntax for the Monastery}

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