Re^3: I am confused by a "Learning Perl" sample showing "unshift"

For reasons of symmetry this

unshift @a, @b means @a = ( @b, @a )

Much the same way as

push @a, @b means @a = ( @a, @b )

So no implicit reversing of @b.

HTH :)

Cheers Rolf
_{(addicted to the Perl Programming Language :)

Wikisyntax for the Monastery}

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Re^4: I am confused by a "Learning Perl" sample showing "unshift" by rsFalse (Chaplain) on Jan 23, 2021 at 21:48 UTC
Therefore: `unshift @a, @b` same* as `push @b, @a` *But see clarification from choroba:	[reply] [d/l] [select]
Re^5: I am confused by a "Learning Perl" sample showing "unshift" by choroba (Cardinal) on Jan 23, 2021 at 21:51 UTC
:-) No, as the first one changes @a, but the second one changes @b. The result is the same, but ends up in a different container. `map{substr$_->[0],$_->[1]\|\|0,1}[\\|\|{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^ARGV,3]`	[reply] [d/l]
Re^5: I am confused by a "Learning Perl" sample showing "unshift" by LanX (Saint) on Jan 23, 2021 at 22:10 UTC
Yes good point! :) ( provided choroba's comment, that the targets are swapped. ) Cheers Rolf _{(addicted to the Perl Programming Language :) Wikisyntax for the Monastery}	[reply]