Re: Why are list items passed to die() combined into a string?

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Re^2: Why are list items passed to die() combined into a string? by Lotus1 (Vicar) on Jan 13, 2015 at 18:52 UTC
Thanks, that verifies what I see. I had read the article that node was in response to but I didn't make it down that far. Another node states that `die()` is just doing what `print()` does and concatenates its inputs for display. Update: I found the following at General Variables in the %SIG section: The routine indicated by $SIG{__DIE__} is called when a fatal exception is about to be thrown. The error message is passed as the first argument.	[reply] [d/l] [select]
Re^3: Why are list items passed to die() combined into a string? by kennethk (Abbot) on Jan 13, 2015 at 19:25 UTC
Thing to note: neither $" or $, will impact the concatenation seen by `$SIG{__DIE__}`(e.g. `join '', @_`). This contrasts print, where `print "@_"` or `print @_` can have their behavior impacted. I far prefer overriding die to working with `$SIG{__DIE__}` myself, since the latter's behavior isn't what I usually actually want to impact. #11929 First ask yourself `How would I do this without a computer?' Then have the computer do it the same way.	[reply] [d/l] [select]
Re^4: Why are list items passed to die() combined into a string? by Lotus1 (Vicar) on Jan 13, 2015 at 22:31 UTC
Ah, good point. Overriding functions will be my next project. I had considered using `"@_"` to pass to my email routine just to let my future self know it needs to be a single string. But since `@_` has already been concatenated that doesn't make sense. Now I'm thinking passing `$_[0]` might be better.	[reply] [d/l] [select]