In your code you have this block (I've shortened the print statements for clarity):

        if ($ele eq 0){
        } else {
            if ($ele eq 1){
                print "Condition: ele is 1\n";
            } else {
                print "Condition: ele is neither 1 nor 0\n";
            }
      
        }
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This is confusing because of the empty block straddling the first 2 lines. There are a couple of ways to avoid it in general. One is to negate the condition:

        if ($ele ne 0){
            if ($ele eq 1){
                print "Condition: ele is 1\n";
            } else {
                print "Condition: ele is neither 1 nor 0\n";
            }
      
        }
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The other is to turn the if into an unless:

        unless ($ele eq 0){
            if ($ele eq 1){
                print "Condition: ele is 1\n";
            } else {
                print "Condition: ele is neither 1 nor 0\n";
            }
      
        }
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Either of these removes the empty block, so that's a plus. But we can go farther. The logic can be simplified because really you have only 2 conditions as indicated by my rewritten print statements. So we can remove the outer condition by folding it into the else like so:

            if ($ele eq 1){
                print "Condition: ele is 1\n";
            } elsif ($ele ne 0) {
                print "Condition: ele is neither 1 nor 0\n";
            }
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Finally, deducing from your previous code that $ele is only ever a whole number you can switch to using numerical comparisons rather than string comparisons (== instead of eq, etc.). Perhaps this is the clearest:

            if ($ele == 1) {
                print "Condition: ele is 1\n";
            } elsif ($ele > 1) {
                print "Condition: ele is neither 1 nor 0\n";
            }
[download]

I understand that you are just hacking about with this code but wanted to point out these alternative ways of going about the logical if-blocks. The simpler you can make it the fewer bugs can creep in and that has to be a good thing.