Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:
%replaces =
{ "foo"
=> ( 'W100' => 'W102',
'W101' => 'W103',
...),
"bar"
=> ( 'W120' => 'W99',
'W121' => 'W104',
...),
... }
For instance, the hash shown below should led to the string W100|W101|W120|W121.
Would it be possible to find a one-liner expression, or at least, a graceful piece of code to perform this ?
I tried this :
my $expr = join '|', keys(%{$replaces{$_}}) foreach keys(%replaces);
But $expr remains undefined after this line.
I ended up hardcoding the expecting first-level values for the current run, but it's a dirty solution :
my $expr = join '|', (keys(%{$replaces{'foo'}}), keys(%{$replaces{'bar'}}));
Thanks for any help on that !
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Re: One-liner to join keys on a two-dimensionnal hash ?
by ikegami (Patriarch) on Dec 29, 2021 at 14:44 UTC | |
by Anonymous Monk on Dec 29, 2021 at 15:01 UTC | |
by ikegami (Patriarch) on Dec 29, 2021 at 15:07 UTC | |
by eyepopslikeamosquito (Archbishop) on Dec 29, 2021 at 23:20 UTC | |
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Re: One-liner to join keys on a two-dimensionnal hash ?
by johngg (Canon) on Dec 29, 2021 at 15:11 UTC | |
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Re: One-liner to join keys on a two-dimensionnal hash ?
by LanX (Saint) on Dec 29, 2021 at 15:31 UTC |