Sorry, I missed that :)
- if no D or U are present, then all s becomes i
The following one was not properly converted:
old:ssssssDDDDDDDDDDDDDDsssssssssssssDDDDDssssssssssssssssssssssssssss
+ssssssssssssssDDDDDDDssssssssssssssssssssssssssssssssssssssssssssssss
+sssssssssssssDDDDDDssssssssssssssssssssssssssssssssssssssssssssssssss
+sssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss
+ssssssssssss
new:OOOOOOMMMMMMMMMMMMMMIIIIIIIIIIIIIMMMMMOOOOOOOOOOOOOOOOOOOOOOOOOOOO
+OOOOOOOOOOOOOOMMMMMMMIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII
+IIIIIIIIIIIIIMMMMMMssssssssssssssssssssssssssssssssssssssssssssssssss
+sssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss
+ssssssssssss
| [reply] [d/l] [select] |
I still don't understand the rules. If the input is
DDssDD
what should it become? Are the "s" prior to "D" or following a "D"?
In the new/old example, why are the final "s" not replaced? Don't they follow a "D"?
Please, try to be more precise.
Also, you can easily shorten the data, 2 consecutive characters of each type would do.
map{substr$_->[0],$_->[1]||0,1}[\*||{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^*ARGV,3]
| [reply] [d/l] [select] |
Ok, let me try again with some examples of how data look now (old) and should look (new):
-case 1: only 's'
old:sssss
new:iiiii
-case 2: only 's' and 'U'
old:sssUUss
new:iiiMMoo
-case 3: only 's' and 'D'
old:sssDDss
new:oooMMii
-case 4: 's', 'D' and 'U' (all possible characters)
old:sssssDDDDDDDssssUUUss
new:oooooMMMMMMMiiiiMMMoo
OR
old:sssssUUUUUUUssssDDDss
new:iiiiiMMMMMMMooooMMMii
For some reason, the code I wrote changes many but not all cases... Not that you cannot see s+D+s+D+s+<code> sequence, or <code>s+U+s+U+s+<code>. <code>D and U alternate. | [reply] [d/l] [select] |