Re: You can't assign $_ to a hash in a foreach statement

No.

For starters, a foreach loop never assigns to the variable. It makes it an alias to the value for that iteration.

And even if it did assign, the original value is restored at the end of the loop, so it would be of no use to you.

$_ = "abc";
say;

for (qw( def ghi )) {
   say;
}

say;
[download]

Output:

abc
def
ghi
abc
[download]

Comment on Re: You can't assign $_ to a hash in a foreach statement Select or Download Code

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Re^2: You can't assign $_ to a hash in a foreach statement by markdibley (Sexton) on Apr 08, 2022 at 17:03 UTC
You are right about the scope and actually for my purposes it is not necessary. I shouldn't have included the die at the end as it's output and the modified hash structure is not required. Sorry. perldoc says "The foreach loop iterates over a normal list value and sets the scalar variable VAR to be each element of the list in turn." So I was expecting to be able to use a hash reference as VAR. It doesn't mention aliasing. But as you say, the answer does appear to be No.	[reply]
Re^3: You can't assign $_ to a hash in a foreach statement by ikegami (Patriarch) on Apr 08, 2022 at 17:09 UTC
perldoc says "The foreach loop iterates over a normal list value and sets the scalar variable VAR `$var->{$y}` isn't a variable. the modified hash structure is not required Did you just say it's not necessary to change `$var->{$y}`? Then why do you do it? t doesn't mention aliasing. Maybe, but it does mention the variable acts as an alias. If any element of LIST is an lvalue, you can modify it by modifying VAR inside the loop. Conversely, if any element of LIST is NOT an lvalue, any attempt to modify that element will fail.	[reply] [d/l] [select]