Re: Each on anonymous hash is causing endless loop.

Why strange? It's a new hash every iteration. This is expected behavior.

Comment on Re: Each on anonymous hash is causing endless loop.

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Re^2: Each on anonymous hash is causing endless loop. by LanX (Saint) on Aug 24, 2022 at 21:22 UTC
Thanks, good explanation! I was expecting some kind of constant folding ... `C:\>perl -M5.012 my $x = 5; while ( say {a=>1,b=>2} ) { die "abort" unless --$x } __END__ HASH(0xf5b3d0) HASH(0xf5b508) HASH(0xf5b3d0) HASH(0xf5b508) HASH(0xf5b3d0) abort at - line 2. C:\>` [download] Cheers Rolf _{(addicted to the Perl Programming Language :) Wikisyntax for the Monastery}	[reply] [d/l]