Re: why can't I shift a split?

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Re^2: why can't I shift a split? by tybalt89 (Monsignor) on Aug 25, 2022 at 16:32 UTC
But `$_='something,something else'; @_ = shift @ {[split /,/ ]};` [download] does work.	[reply] [d/l]
Re^3: why can't I shift a split? by misterperl (Friar) on Aug 25, 2022 at 16:58 UTC
TY Kind and Wise Monks for these replies. Ken- it's reassuring to know that at least in some Perl-verse this is legal or at least considered. What I'm seeking is the LAST array element; I want shift to toss the top one. this is similar to something else I often do successfully: `@_ = split /,/,join "\n",$myscalar` [download] I was trying to do something similar with shift.. I also tried `shift @_ = split /,/,join "\n",$myscalar` [download] Which I thought had the best chance. Mr TVVALUT has a solution I'll try... I recognize the list/ARRAY difference which is why I was trying various "@{}" constructs to coerce it. Seems like if I can split a join, then I ought to be able to shift a split! TY all!	[reply] [d/l] [select]
Re^4: why can't I shift a split? by tybalt89 (Monsignor) on Aug 25, 2022 at 17:04 UTC
"LAST array element" `my $last = ( split /,/,join "\n",$myscalar )[-1];` [download]	[reply] [d/l]
Re^5: why can't I shift a split? by LanX (Saint) on Aug 25, 2022 at 17:33 UTC
Re^6: why can't I shift a split? by tybalt89 (Monsignor) on Aug 25, 2022 at 18:05 UTC
Some notes below your chosen depth have not been shown here
Re^4: why can't I shift a split? by Anonymous Monk on Aug 26, 2022 at 16:43 UTC
If you want the last element of a `split()`, try this: `( split ... )[-1]`.	[reply] [d/l] [select]