Re: How to determine if 'strict' is enabled

You can't use %INC.

$ perl -le'no strict;      print $INC{ "strict.pm" } ?1:0'
1   # False positive

$ perl -le'{ use strict; } print $INC{ "strict.pm" } ?1:0'
1   # False positive

$ perl -le'use JSON;       print $INC{ "strict.pm" } ?1:0'
1   # False positive

$ perl -le'use v5.20;      print $INC{ "strict.pm" } ?1:0'
0   # False negative
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You can use ( caller(0) )[8] in a sub.

$ perl -le'
   sub f { ( ( caller(0) )[8] & 0x602 ) == 0x602 }
   print f ?1:0;
'
0

$ perl -le'
   sub f { ( ( caller(0) )[8] & 0x602 ) == 0x602 }
   use strict;
   print f ?1:0;
'
1

$ perl -le'
   sub f { ( ( caller(0) )[8] & 0x602 ) == 0x602 }
   use v5.20;
   print f ?1:0;
'
1
[download]

0x2 is strict refs, 0x200 is strict subs, and 0x400 is strict vars.

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Re^2: How to determine if 'strict' is enabled by stevieb (Canon) on Jun 07, 2023 at 05:16 UTC
This enlightened me. Is this documented anywhere ikegami? If so, it's something I've completely overlooked, glossed over or for some reason over the years completely ignored.	[reply]
Re^3: How to determine if 'strict' is enabled by kcott (Archbishop) on Jun 07, 2023 at 06:15 UTC
G'day stevieb, "Is this documented anywhere ikegami?" I looked this up after ++ikegami's response. See caller for element-8, `$hints`, and subsequent discussion. See "strict's source code" for the numbers (`0x2`, `0x200`, and `0x400`). — Ken	[reply] [d/l] [select]
Re^4: How to determine if 'strict' is enabled by LanX (Saint) on Jun 07, 2023 at 11:27 UTC
And especially `$^H` is enlightening, too. Each time a statement completes being compiled, the current value of `$^H` is stored with that statement, and can later be retrieved via `(caller($level))[8]` so it also depends at what time you need to check the strictness. Cheers Rolf _{(addicted to the 𐍀𐌴𐍂𐌻 Programming Language :) Wikisyntax for the Monastery}	[reply] [d/l] [select]
Re^2: How to determine if 'strict' is enabled by kcott (Archbishop) on Jun 07, 2023 at 04:31 UTC
G'day ikegami, ++ Thanks. That's just the sort of thing I was looking for. — Ken	[reply]