in reply to Re: modulus question
in thread modulus question

vinoth in a case like this by not providing any code there is a chance that the OP will show us what he has tried and thus allow us to provide much better help than we can by just giving a dollop of code.

Very often the errors beginners make fall into common patterns and tell you a lot about how they are thinking and where the root of their problem really lie. By just giving a solution, even if we take time to explain how the solution works, beginners will run off happy, but none the wiser.

Perl is the programming world's equivalent of English

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Re^3: modulus question
by vinoth.ree (Monsignor) on Feb 03, 2015 at 08:12 UTC
    Hi GrandFather,

    Yes I agree with you, I regret for that. As per my understanding I though he just confused if(....) condition with modulus(%) operator. That's why I just given him the explanation.


    All is well