Re^2: Modification of a read-only value attempted?!?

I don't see an explanation for the difference between for my $x (1)... and for my $x (0 .. 1)... here.

Update:
haj explained it perfectly in Re^3: Modification of a read-only value attempted?!?

Greetings,
-jo

$gryYup$d0ylprbpriprrYpkJl2xyl~rzg??P~5lp2hyl0p$

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Re^3: Modification of a read-only value attempted?!? by ikegami (Patriarch) on Jan 09, 2024 at 19:39 UTC
While `0` and `1` evaluate to a constant, `0..1` evaluates to two scalars which aren't constants. That said, `for (0..1)` doesn't actually use the range operator as an optimization. But the result is the same.	[reply] [d/l] [select]