in reply to Re^8: Reason for this discrepancy with scalar?
in thread Reason for this discrepancy with scalar?

Yes I remember digging into it and the fields Pragma.

And ....

# this will generate a compile-time error my Foo $foo = Foo->new;

I could see a use case in extending this already existing syntax for other purposes, like

But probably I'm naive.

Cheers Rolf
(addicted to the Perl Programming Language :)
see Wikisyntax for the Monastery