in reply to Re^8: Reason for this discrepancy with scalar?
in thread Reason for this discrepancy with scalar?
And ....
# this will generate a compile-time error my Foo $foo = Foo->new;
I could see a use case in extending this already existing syntax for other purposes, like
But probably I'm naive.
Cheers Rolf
(addicted to the Perl Programming Language :)
see Wikisyntax for the Monastery
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