in reply to while-loop regex substitution with 'g' option
With s///g, it performs all the substitutions.
With m//g, it normally returns all the matches.
This is very similar.
I said "normally" because m//g in scalar context can't return all the matches without external help. That's why a loop needs to be introduced.
You're looking for
$x =~ s{ \s* (foo\w) \s* }{ push @captured, $1; "" }xeg;
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Re^2: while-loop regex substitution with 'g' option
by ibm1620 (Hermit) on Apr 22, 2024 at 04:43 UTC |