Re: JAVA [[a-z]&&[^aeiou]] equivalence

You need at least Perl 5.18 to use regex sets:

#!/usr/bin/perl
use warnings;
use strict;
use experimental qw{ regex_sets };

my @match = grep /(?[ [^aeiou] & [a-z] ])/, map chr, 0 .. 255;
print "match = @match\n";
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Output:

match = b c d f g h j k l m n p q r s t v w x y z
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map{substr$_->[0],$_->[1]||0,1}[\*||{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^*ARGV,3]

Comment on Re: JAVA [[a-z]&&[^aeiou]] equivalence Select or Download Code

Replies are listed 'Best First'.
Re^2: JAVA [[a-z]&&[^aeiou]] equivalence by Arunbear (Prior) on Jul 10, 2024 at 10:10 UTC
And in 5.36 they were upgraded to non-experimental.	[reply]
Re^2: JAVA [[a-z]&&[^aeiou]] equivalence by Discipulus (Canon) on Jul 10, 2024 at 10:15 UTC
Hello, nice info choroba. Glancing the doc you linked the following is even neater to my eyes: `my @match = grep /(?[ [a-z] - [aeiou] ])/, map chr, 0 .. 255;` [download] L* There are no rules, there are no thumbs.. Reinvent the wheel, then learn The Wheel; may be one day you reinvent one of THE WHEELS.	[reply] [d/l]
Re^2: JAVA [[a-z]&&[^aeiou]] equivalence by parv (Parson) on Jul 10, 2024 at 09:46 UTC
Neat; learned something(regex sets).	[reply]
Re^2: JAVA [[a-z]&&[^aeiou]] equivalence by vincentaxhe (Scribe) on Jul 10, 2024 at 09:54 UTC
great!	[reply]