in reply to [OT] Astronomical puzzling about daylight hours at different latitudes
While the sun can reach the zenith only in the tropics¹ at noon (your shadow is between your legs) the perceived curve will become always flatter when distancing from the equator.
This curve is always under the horizon at polar night and always above in polar summer. That's because the rotation axis of the earth has an inclination compared to the sun³
Even a flat horizon is practically perceived like the earth's body hiding the sun like a mountain ridge surrounding you in winter. But in summer the horizon "lowers" to a valley and you are subjectively the one standing on a mountain top.
That's a gradual effect from poles to equator.
The combined effect of flattened curve, "moving" horizon and definition of sun rise or sunset effect the calculation. ²
Plus the flatter the curve, the longer does the sun need to fully pass the horizon from one tip to the other.
I found a German website where you can play with coordinates and check all parameters. The graphics are nice at displaying the perceived curve.
https://www.datum-und-uhrzeit.de/?coordinates=true
I compared points near Berlin and Rome with "integer" coordinates
HTH :)
Cheers Rolf
(addicted to the Perl Programming Language :)
see Wikisyntax for the Monastery
¹) by definition!
²) it's even more complicated because of precession, nutation and uneven shape of the rotating potato ellipsoid we live on
³) more correctly the ecliptic, the plane in which earth is rotating around the sun
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Re^2: [OT] Astronomical puzzling about daylight hours at different latitudes
by LanX (Saint) on Sep 06, 2024 at 16:01 UTC |