Re^4: Adjusting variable context when working with JSON data?

I thought that you "\" to de-reference, or maybe that's just for hashes? But in any case I think you're right, I need to write some more Perl to get used to this. I've only started to pick it up out of curiosity, and so far I've only written a few things here and there to get a taste of the basics. Thanks for the help!

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Re^5: Adjusting variable context when working with JSON data? by hippo (Archbishop) on Dec 08, 2024 at 11:32 UTC
Preceding with a backslash creates a reference to the operand. De-referencing is the opposite of this. Do have a read of the intro to references tutorial, perlreftut and perlref for getting started with references. 🦛	[reply]
Re^6: Adjusting variable context when working with JSON data? by unmatched (Sexton) on Dec 09, 2024 at 10:56 UTC
Oh, I see. I got it completely backwards. For some reason I thought that `$` was used only for scalar values. Will read more on this, thanks again!	[reply]
Re^7: Adjusting variable context when working with JSON data? by marinersk (Priest) on Dec 10, 2024 at 07:31 UTC
For some reason I thought that `$` was used only for scalar values. Well, yes. A reference is a scalar variable. It contains one value: The reference (in the old days we might have called it the "address") to something else. The nature of that "something else" is irrelevant to the typing of the reference -- it is a scalar.	[reply]