Re: Elegant way to escape a string in a regex

Problems:

The first thing that happens is that the end of the operator is found. The only characters to which the parser pays attention at this stage are «\» and the delimiter(s). This means the first «\» in your selector is taken as the end of operator.
«\Qq{//div[@id="abc"]}\E» isn't valid Perl code, but it's expected to be when using the «e» modifier.

It might be best to split out the replacement.

my $repl = '//div[@id="abc"]';

s/.../$repl/
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The following would also work:

s{...}{ q{//div[@id="abc"]} }e
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s{...}{ '//div[@id="abc"]' }e
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Changed the delimiter to allow «\» to be used unescaped, and removed «\Q\E».

If you change the replacement expression's delimiter to «'», it will act as a single-quoted string literal instead of a double-quoted string literal.

s{...}'//div[@id="abc"]'
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Probably best to avoid this one because it's pretty obscure.

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Re^2: Elegant way to escape a string in a regex by bliako (Abbot) on Apr 14, 2025 at 19:22 UTC
Thanks. I did not know the last one you gave (`s{...}'//div[@id="abc"]'`). I should not have used `\Q\E` then. I did use it in case there were things like `$1` in the replacement string. But `q{//div=[@id="$1"]}` gives no problem and escapes that too. So, just to confirm, q{} is absolutely safe for providing a substitution string which nothing in it will be interpreted by the regex (e.g. $1) or by perl (e.g @id): all contents of q{} will be literal, nothing interpreted.	[reply] [d/l] [select]
Re^3: Elegant way to escape a string in a regex by ikegami (Patriarch) on Apr 14, 2025 at 19:34 UTC
In single-quoted string literals (e.g. «`q{}`»), only «`\`» and the delimiter(s) (i.e. «`{`» and «`}`» when using «`q{}`») are significant. You may need to escape instances of the former, while instances of the latter needs to be escaped or balanced. Finally, you must not escape anything except the aforementioned characters.	[reply] [d/l] [select]