in reply to Re^7: Largest integer in 64-bit perl
in thread Largest integer in 64-bit perl

> The most sensible approach is to break out bigint/bigrat when it is needed. ... Python does it

Really? That's surprising me a bit... can you provide evidence for this?

From my experience is Python "more" typed than Perl, leading to 3/2==1 because it assumes that's an integer operation only.

edit
OK, looks good in Python3, seems they also fixed the division issue from Python2
:~$ python3 Python 3.12.3 (main, Feb 4 2025, 14:48:35) [GCC 13.3.0] on linux Type "help", "copyright", "credits" or "license" for more information. >>> 3/2 1.5 >>> (2**4711+1)-2**4711 1 >>>

update

LOL, I suppose nobody is perfect...

>>> (2**(128/2)+1)-2**64 0.0 >>> (2**(64)+1)-2**64 1 >>> (2**(128//2)+1)-2**64 1 >>>

Seems like 128/2 being a float, breaks the workaround xD

Cheers Rolf
(addicted to the Perl Programming Language :)
see Wikisyntax for the Monastery