Difference between -e and -E when invoking Perl

adefaria has asked for the wisdom of the Perl Monks concerning the following question:

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Re: Difference between -e and -E when invoking Perl by hippo (Archbishop) on Mar 09, 2015 at 18:27 UTC
There is no discussion of what -E does differently to -e. Sure there is. Here's the relevant bit of perlrun: -E commandline behaves just like -e, except that it implicitly enables all optional features (in the main compilation unit). See feature.	[reply]
Re: Difference between -e and -E when invoking Perl by karlgoethebier (Abbot) on Mar 09, 2015 at 18:27 UTC
For example: `karls-mac-mini:monks karl$ perl -E 'say qq(Hello World!)' Hello World! karls-mac-mini:monks karl$ perl -e 'say qq(Hello World!)' syntax error at -e line 1, near "say qq(Hello World!)" Execution of -e aborted due to compilation errors. karls-mac-mini:monks karl$ perl -e 'print qq(Hello World!)' Hello World!` [download] ŤThe Crux of the Biscuit is the Apostropheť	[reply] [d/l]
Re: Difference between -e and -E when invoking Perl by Corion (Patriarch) on Mar 09, 2015 at 18:27 UTC
I'm not sure which "man page" you looked at that only discussed `-E`. The man page provided with Perl, perlrun certainly explains both, `-e` and `-E`. It's also quite weird to only explain `-E` and not `-e`, as they are so similar.	[reply] [d/l] [select]