Hello ferdi, and welcome to the Monastery!

To expand a little on the answers given above: if you change the print statement to this:

printf "%d %d %d %.15f %.15f %s %.0f %.0f %.0f %.0f\n",
        $date, $time1, $time2, $stretch, $stretcher, $identifier, $ope
+n, $high, $low, $close;
[download]

you will see:

 1:39 >perl 1187_SoPW.pl
20120620 93100 100000 7.000000000000000 43.000000000000000 Red 84 84 8
+4 84
20120621 93100 100000 28.999999999999091 32.000000000000909 Red 81 81 
+80 80
20120622 93100 100000 27.999999999998181 39.000000000000000 Green 79 7
+9 78 79
20120625 93100 100000 4.999999999999091 76.000000000000909 Red 79 79 7
+8 78

 1:40 >
[download]

which shows why the numbers in the first line are printed as integers. One way to convert a floating-point number to the closest integer is to add 0.5 and then truncate:

 1:40 >perl -wE "my $fp = 28.999999999999091; my $int = int($fp + 0.5)
+; say $int;"
29

 1:47 >
[download]

Hope that helps,