The point I was getting at is that 2**1024000, is already logarithmic. Ie. 1024000 is log₂ of your number.

Thus, to convert it to log₁₀(), you only need divide it by log₂( 10 ).

Then all you need is:

sub log2{ log( $_[0] ) / log( 2 ) }
sub log2ToLog10{ $_[0] / log2( 10 ) }

print log2ToLog10( 1024000 );;
308254.715559917
[download]

And once you have that, displaying it in human readable form becomes:

my $log10 = log2ToLog10( 1024000 );

printf "%.16fe%d\n",  10**( $log10 - int( $log10 )), int( $log10 );;
5.1946933632179482e308254
[download]

Which is pretty accurate according to wolfram/alpha:

A good observation and valid question, but, no, my calculations are not all powers of 2. Thanks for the math reminder. :-)

Can I ask how you are arriving at these huge numbers in your program?

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