in reply to Re^2: What is (a => b => c) ?
in thread What is (a => b => c) ?
Not at all.
Prepending & to a sub call causes the sub call to ignore the sub's prototype.
Prepending & to a sub call with no parameter list specified (not even ()) causes the sub call to ignore the sub's prototype, and forgoes the creation of a localized @_.
These are not thing you should ever need to do. Because it must be followed by a sub call, & has the side effect of forcing the following word to be treated as the name of a sub, but that's just a side effect.
|
|---|