Dear Monks!

I'm now trying to call perl functions from c code. I've already built perl with MSVS2013 Professional on Windows 7 64 bit. I'm now testing perlembed code, and I've run into problem.

Let's look at Calling a Perl subroutine from your C program.

    #include <EXTERN.h>
    #include <perl.h>
    static PerlInterpreter *my_perl;
    int main(int argc, char **argv, char **env)
    {
        char *args[] = { NULL };
    PERL_SYS_INIT3(&argc,&argv,&env);
        my_perl = perl_alloc();
        perl_construct(my_perl);
        perl_parse(my_perl, NULL, argc, argv, NULL);
    PL_exit_flags |= PERL_EXIT_DESTRUCT_END;
        /*** skipping perl_run() ***/
        call_argv("showtime", G_DISCARD | G_NOARGS, args);
        perl_destruct(my_perl);
        perl_free(my_perl);
    PERL_SYS_TERM();
    }
[download]

My trouble is if I call some sub, it only actually executes on perl_destruct(my_perl);. I did not found what causes such behaviour in perlembed. And I don't quite understand what is happening, so I tried place perl_run(my_perl), or GL_EVAL in different places.

Okay,- I've thought,- let's try Maintaining a persistent interpreter example. I don't want to bloat my question so here is link Maintaining-a-persistent-interpreter-example
This example crashes here:

             
if(SvTRUE(ERRSV))
fprintf(stderr, "eval error: %s\n", SvPV_nolen(ERRSV));
[download]

When I comment this out, it still does nothing, even on perl_destruct();

So my first question: is there any manual for me to understand, what happens when call_argv() is called? I'm now reading perlguts, perlcall, however, I cannot find it. If you can, please specify me right way.:)

And second question: when call_argv(); actually executes function? Or can I force somehow to do it? Thank you!

EDIT
Okay, function is called with call_argv(). It is problem with output. Print in function, does not show up until perl_destruct()
If print STDERR is used, output appears immediatly.
/EDIT