Yes if there is a .txt file, move the file called outFile to the new directory. Correct. | [reply] |
Hi Bama_Perl,
What I don't understand is do you want the file "outFile" moved or copied? Because, if you move it to say the first directory that has '*.txt', what happens to another say "fourth" directory that also has '*.txt'?
Secondly, I think you should be using a perl core module like File::Copy to achieve your aim instead of using mv command in system like you are doing.
Third, you may use File::Find module to do the searching of directories for you.
Lastly, use three arguments open function and a lexical scoped file-handler (this is an old wisdom that still holds true in a way today)
If you tell me, I'll forget.
If you show me, I'll remember.
if you involve me, I'll understand.
--- Author unknown to me
| [reply] |
Hi 2teez,
I want to copy the $outFile to a new directory. I don't want to move it to a directory that has *.txt. In other words, as I loop through each directory, if that directory has a *.txt file, then I want to move the $outfile within that directory to a new directory. If that directory does not have a *.txt file, then nothing will be moved to a new directory. I'll look into File::Copy to see how that can help me. Thanks!
| [reply] |
| [reply]
[d/l]
[select] |
#!/usr/bin/perl
use warnings;
use Cwd;
$out = "outFile";
$newdir = $newdirectory;
open(TABLEA, "dirlist");
@tablea = <TABLEA>;
foreach $dir (@tablea) {
chomp @tablea;
chdir $dir;
print(cwd);
print "\n";
if (glob("*.txt")) {
system("mv $out $newdir");
}
}
If I add the chomp and I print the current working directory, the only directory that gets printed is the first directory, multiple times(as many times there are files in the main directory). Any other thoughts? Thanks. | [reply]
[d/l] |