in reply to decimal to binary conversion

To see your program as Perl sees it, deparse it:

c:\@Work\Perl\monks>perl -wMstrict -MO=Deparse,-p -e "print 'Enter decimal number less than 256: '; my $decimal; $decimal=<STDIN>; chomp $decimal; print $decimal & 128 <=> 0; print $decimal & 64 <=> 0; print $decimal & 32 <=> 0; print $decimal & 16 <=> 0; print $decimal & 8 <=> 0; print $decimal & 4 <=> 0; print $decimal & 2 <=> 0; print $decimal & 1 <=> 0; " BEGIN { $^W = 1; } use strict 'refs'; print('Enter decimal number less than 256: '); my($decimal); ($decimal = <STDIN>); chomp($decimal); print(($decimal & 1)); print(($decimal & 1)); print(($decimal & 1)); print(($decimal & 1)); print(($decimal & 1)); print(($decimal & 1)); print(($decimal & 1)); print(($decimal & 1)); -e syntax OK
See O and B::Deparse.

Update: Why does every expression like  128 <=> 0 become the constant 1? Because the Perl compiler, like most compilers today, is smart enough to know that the result of the comparison of a constant to a constant is just going to be yet another constant, 1 in all these cases. (Update: I believe this process is called constant folding.)


Give a man a fish:  <%-(-(-(-<